(2x^-3y/3^-1z^4)^-4

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Solution for (2x^-3y/3^-1z^4)^-4 equation: 


D( x )

((2*x^-3*y)/(3^-1))*z^4 = 0

x = 0

((2*x^-3*y)/(3^-1))*z^4 = 0

((2*x^-3*y)/(3^-1))*z^4 = 0

6*x^-3*y*z^4 = 0 // : 6*y*z^4

x^-3 = 0

x należy do O

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(((2*x^-3*y)/(3^-1))*z^4)^-4 = 0

1/1296*x^12*y^-4*z^-16 = 0 // : 1/1296*y^-4*z^-16

x^12 = 0

x = 0

x in { 0} 

x belongs to the empty set

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